Indoor Climate Product info in PDF form
 
SWEGON AB Indoor Climate Systems 2004 - Air distribution products - Rev. 5 June, 2007
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Calculations aids
Graphs and formulae

Pressure drop graph for circular section ducts

A = Size, mm


Pressure drop graph for circular section bends

 


Pressure drop graph for circular section bends

 


Pressure drop graph, dimensions changes in circular ducts

Area increase

A = Number of dimension changes.
(Example from  016 - 020 = 1 dim.changes.)


Area reduction

A = Number of dimension changes.
(Example from  020 - 016 = 1 dim.changes.)


Pressure drop graphs for circular T and Y jones

Pressure drop includes dimensionen reduction where S < 3 x D, as shown in the diagram.








Pressure drop graph for rectangular section ducts


Ducts with the same equivalent diameter De may have different cross section areas. The velocity curves plotted above are therefore approximate with a maximum error of <5%.

Pressure drop graph for rectangular section bends

Mollier graph

A = Wet thermometer
B = Iced-over thermometer.
C = Water vapour saturation pressure, kPa


Symbols:
h
= enthalpy for1 kg dry air, kJ/kg
x
= water content of 1 kg dry air, kg/kg
j
= relative humidity
J
= dry thermometer temperature, °C
v
= wet thermometer temperature, °C
The graph is correct at atmospheric pressure = 101.3 kPa = 1013 mbar.


Formulae overview

Air flow, q m3/s
q = A · v
A = cross section area, m2
v = air velocity, m/s


Dynamic pressure, pd Pa
Pd =  P v2/2
r = air density kg/m3
v = air velocity, m/s


Hydraulic diameter, dh m
dh =  4 · A/O
A = cross section area, m2
O = circumference of duct, m
dh for rectangular ducts
dn =  2 · a · b / a + b
a and b are the duct sides
dh for circular ducts
dh = d = duct diameter


Total pressure drop - supply air, pt Pa
pt = ps + pd
ps = static pressure drop Pa
pd = dynamic pressure drop, Pa


Total pressure drop - exhaust air pt Pa
pt = (-ps) + pd
ps = negative static pressure drop, Pa
pd = dynamic pressure drop, Pa


Cross section area, circular duct, A m2
A = p · d2 / 4
d = duct diameter, m


Circumference, circular duct, O m
O = p · d
d = duct diameter, m


Air density, r  kg/m3
rt = 1.293 · B / 1013 · 273 / 273 + t
B = barometer reading, mbar
t = air temperature, oC


Cooling/heating effect, P kW

P = q · r · Cp · DT

q = air flow, m3/s
= air density, kg/m3
Cp = specific heat capacity of air, kJ/kg,K
(» 1.0 at 20 °C)
Dt = temperature difference, oC, between supply and exhaust air


Throw at different terminal velocities, Lx m
Lx = l0.2 · 0.2/Vx
l0.2 = throw to terminal velocity 0.2 m/s in accordance with catalogue data, m
Vx = selected alternative, m/s




   

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